evaluate triple integral of xyz dxdydz over the volume enclosed by the coordinate planes and the plane x/a+y/b+z/c=1
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Using triple integrals and Cartesian coordinates, find the volume of the solid bounded by
xa+yb+zc=1
and the coordinate planes x=0,y=0,z=0
My take
I have set the parameters to
0≤x≤a
0≤y≤b(1−xa)
0≤z≤c(1−yb−xa)
and evaluated
∫a0∫b(1−xa)0∫c(1−yb−xa)01dzdydx
and gotten 0 as my final answer but the actal answer is abc/6
hope
it was helpful
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