evaluate using appropriate identity (3a+4b)³
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1
Answer:
Using identity--(a+b)³=a³+b³+3a²b+3ab²
=(3a)³+(4b³)+3(3a)²(4b)+3(3a)
(4b)²
=27a³+64b³+108a²b+144ab²
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Answered by
0
Answer:
Identity » (a+b)³ = a³+b³+3a²b+3ab²
(3a+4b)³
= (3a)³+(4b)³+3(3a)²(4b)+3(3a)(4b)²
= 27a³+64b³+108a²b+144ab²
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