Question

Evaluate using dentities:(101) 2

Answer 1

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┗─━─━─━─━∞◆∞━─━─━─━─┛

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What to do :

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$\bf \: Evaluate \: using \: identities:(101) {}^{2}$

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Solution :

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$\bf \:\color{red} \implies {101}^{2}$

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$\bf \:\color{red} \implies {(100 + 1)}^{2}$

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$\bf \:\color{orange} using \: identity$

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$\bf \:\color{orange} {(x + y)}^{2} = {x}^{2} + 2xy + {y}^{2}$

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$\bf \:\color{red} \implies {100}^{2} + 2 \times 100 \times 1 + {1}^{2}$

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$\bf \:\color{red} \implies10000 + 200 + 1$

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$\bf \:\color{red} \implies10201$

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✏More Identities

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• $\bf \:\color{green} (x - y) {}^{2} = {x}^{2} - 2xy + {y}^{2}$

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• $\bf \:\color{magenta} {x}^{2} - {y}^{2} = (x + y)(x - y)$

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• $\bf \:\color{green}(x + a)(x + b) = {x}^{2} + (a + b) x + ab$

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• $\bf \:\color{magenta} {(x + y)}^{3} = {x}^{3} + {y}^{3} + 3xy(x - y)$

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• $\bf \:\color{green} {(x - y)}^{3} = {x}^{3} - 3 {x}^{2} y + 3x {y}^{2} - {y}^{3}$

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Answer 2

$\bf \huge {\underline {\underline \red{AnSwEr}}}$

$\bf {101}^{2}$

$\bf {(100 + 1)}^{2}$

$\bf using \: identity$

$\bf {(x + y)}^{2} = {x}^{2} + 2xy + {y}^{2}$

$\bf {100}^{2} + 2 \times 100 \times 1 + {1}^{2}$

$\bf 10000 + 200 + 1$

$\bf 10201$