Question

evaluate using exponent rules. (-2²) x (-2)³​

Answer 1

Answer:

${( - 2}^{2} ) \times {( - 2)}^{3} ) \\ = { ( - 2)}^{2 + 3} \\ = {( - 2)}^{5}$

Step-by-step explanation:

$\tt \: according \: to \: the \: law \: of \: exponent$

Let a/b be any rational number , and m and n be any integers. Then, we have:

$\pink{ \frac{a}{b}^{m} \times \frac{a}{b} ^{n} = \frac{a}{b}^{m + n} }$

Answer 2

ǫᴜᴇsᴛɪᴏɴ →

evaluate using exponent rules. (-2²) x (-2)³

ᴀɴsᴡᴇʀ →

TO DETERMINE

The value of

$\longmapsto\tt{(-2²) \: x \: (-2)³}$

FORMULA TO BE IMPLEMENTED

$\longmapsto\tt{a^n × a^m = a^m+^n}$

We are aware of the formula on indices that

EVALUATION

EVALUATION

\sf{ {( - 2)}^{2} \times {(2)}^{3} }(−2)

2

×(2)

3

$\tt{ = {( 2)}^{2} \times {(2)}^{3} \: \: \: \: \: \big( \: \because \: {( - a)}^{2} = {a}^{2} \big) }=(2) </p><p>2$

$×(2)³ (∵(−a)² = a²)\sf{ = {( 2)}^{2 + 3} }=(2) </p><p>2+3$

$\sf{ = {2}^{5} }=2 </p><p>5$

$\sf{ = 2 \times 2 \times 2 \times 2 \times 2}=2×2×2×2×2$

$\longmapsto\tt{ = 32 =32}$