Question

Evaluate using identities :
1. (0.98)^2

Answer 1

${a - b}^{2} = {a}^{2} + {b}^{2} - 2ab$

${1 - 0.02}^{2}$

${1}^{2} + {0.02}^{2} - 2 \times 1 \times 0.02$

$1 + 0.004 - 0.04$

$1.0004 - 0.04$

$0.9604$

hope this will help you