Question

evaluate using identities 105³​

Answer 1

Step-by-step explanation:

105³= (100+5)³

= (100)³ + (5)³ + 3(100)²(5) + 3(100)(5)²

[(a+b)³= a³ + b³ + 3a²b + 3ab²]

= 1000000 + 125 +150000 + 7500

= 1,157,625

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Answer 2

Answer:

Ans : 11,57,625

Step-by-step explanation:

(105)^3

(100+5)^3 { (a+b)^3 = a^3+b^3+3ab(a+b) }

(100)^3 + (5)^3 + 3(100)(5) ( 100+5 )

1000000 + 125 + 1500 ( 105 )

1000125 + 157500

11,57,625