Math, asked by Mrgoody, 1 year ago

evaluate using identities 63×59

Answers

Answered by chemistrywala
1
(60+3)× (60-1)= (a+b)(a-c)=3717

Mrgoody: Thanks
Answered by DevanshiAgnihotri
1

Answer:

we will use the identity (x+a)(x+b)=x²+(a+b)x+ab

∴63×59=(60+3)(60-1)

=60²+(3-1)60+(-1)×3

=3600+120-3

=3717



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