evaluate using identity (0.99)²
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Answered by
1
(1-0.01)^2= 1^2+(0.01)^2 -2(0.01)(1)= 0.9801
praneethks:
i used (a-b)^2 formula
Answered by
5
ʜᴇʟʟᴏ ᴍᴀᴛᴇ!
(0.99)² = ( 1 - 0.01 )²
( ᴀ - ʙ )² = ᴀ² + ʙ² - 2ᴀʙ
( 1 - 0.01 )² = 1² + 0.01² - 2( 1 )( 0.01 )
= 1 + 0.0001 - 0.02
= 1.0001 - 0.02
= 0.9801
ʜᴏᴘᴇ ɪᴛ ʜᴇʟᴘs
(0.99)² = ( 1 - 0.01 )²
( ᴀ - ʙ )² = ᴀ² + ʙ² - 2ᴀʙ
( 1 - 0.01 )² = 1² + 0.01² - 2( 1 )( 0.01 )
= 1 + 0.0001 - 0.02
= 1.0001 - 0.02
= 0.9801
ʜᴏᴘᴇ ɪᴛ ʜᴇʟᴘs
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