Evaluate using identity 103into107
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Answered by
6
Hii There!!!!
I03 X 107
Since ,[(x+a) (x+b) = x² + (a+b)x + ab]
=> ( 100 + 3 ) ( 100 + 7 )
=> ( 100 )² + ( 3+7 ) 100 + 3 X 7
=> 10000 + 1000 + 21
=> 11021
__________________
Hope it helps
I03 X 107
Since ,[(x+a) (x+b) = x² + (a+b)x + ab]
=> ( 100 + 3 ) ( 100 + 7 )
=> ( 100 )² + ( 3+7 ) 100 + 3 X 7
=> 10000 + 1000 + 21
=> 11021
__________________
Hope it helps
Answered by
0
By using identity
=103*107
=(100+3)(100+7)
=100^2+(3+7)100+7*3
=10000+1000+20
=11020
=103*107
=(100+3)(100+7)
=100^2+(3+7)100+7*3
=10000+1000+20
=11020
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