Math, asked by manjunath9841, 6 months ago

evaluate using identity (3a+2b)2

Answers

Answered by surbhi1906
0

Answer:

9a²+4b²+12ab

Step-by-step explanation:

(3a+2b)²

it is in the form of (x+y)²= x²+y²+2xy

where , x=3a

y=2b

∴(3a+2b)²= (3a)²+(2b)²+2(3a)(2b)

               =9a²+4b²+12ab

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Answered by RehanAk73
0

Answer:(3a−2b)  ² =9a  ²−12ab+4b ²

Step-by-step explanation:

Using  the identity is (x−y)²    =x  ² +y ² −2xy.

Given: (3a−2b)  ²   we apply the above identity by taking  

x=3a and y=−2b

We get, (3a−2b)  ²=(3a)  ² +(2b)  ² −(2×3a×2b)=9a  ²+4b  ² −12ab

Hence, (3a−2b)  ² =9a  ²−12ab+4b ²

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