evaluate using identity (b) (4×-4) (4×-1)
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[ (a+b) -4 ] [ (a+b) +4 ]
= (a+b)² - (4)² ; { using identity (x-y)(x+y) = x²-y² }
= a²+b²+2ab-16
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Answer:
12 is the right answer.
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