Question

Evaluate using identity
$(i) \: {71}^{2}$

(ii)103 x 104
$(iii) {51}^{2} - 49^{2}$

(iv) 103 x 98​

Answer 1

Step-by-step explanation:

i) 71^2 71^2 = (70+1)^2  

       = 702 + 140 + 1^2    

      = 4900 + 140 + 1

= 5041

ii) 103 x 104

= (100 + 3)(100 + 4)

= 1002 + (3 + 4)100 + 12

= 10000 + 700 + 12

= 10712

iii)51^2 - 49^2

= (51 + 49)(51 – 49)

= 100 x 2

= 200

iv) 103 x 98

= (100 + 3)(100 – 2)

= 1002 + (3-2)100 – 6

= 10000 + 100 – 6

= 10094

Hope it help u mate✌

Mark me as brainlist..