Question

evaluate using laws of exponents
( 5÷3)^-5 × ( 9÷5 )^-5
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Answer 1

Step-by-step explanation:

${( \frac{5}{3} )}^{ - 5} \times {( \frac{9}{5}) }^{ - 5} \\ = \frac{ {5}^{ - 5} }{ {3}^{ - 5} } \times \frac{ {9}^{ - 5} }{ {5}^{ - 5} } \\ = {5}^{ - 5} \times {3}^{5} \times {( {3}^{2}) }^{ - 5} \times {5}^{5} \\ = {5}^{ - 5 + 5} \times {3}^{ - 10 + 5} \\ = {5}^{0} \times {3}^{ - 5} \\ = 1 \times \frac{1}{ {3}^{5} } \\ = \frac{1}{ {3}^{5} }$

Hope you get your answer