Question

Evaluate using proper identity 999^2

Answer 1

999^2
=(1000-1)^2
=1000^2 -2*1000*1+ 1^2
= 1000000-2000+1
=998001.

In step 3 (a-b) ^2=a^2 -2ab + b^2. identity is used.
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Answer 2

$\boxed{HOLA !!}$

⏩ANSWER..

✳EVALUATE...

$(999)^2$

We can write this as ,

$(1000 - 1)^2$

Using the indentity,

$(a - b)^2 = (a)^2 - 2ab + (b)^2$

$(1000 - 1)^2 =$

$(1000)^2 - 2*1000*1 + (1)^2$

$1000000 - 2000 + 1$

$1000001 - 2000$

$9,98,001$

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