Math, asked by yaashvi13, 10 months ago

evaluate using suitable identities 103x107​

Answers

Answered by vasuyagnamanemneedi
6

Answer:

103×107

=(100+3)\times (100+7)=(100+3)×(100+7)

Using the identity (x+a)(x+b)=x^2+(a+b)x+ab(x+a)(x+b)=x

2 +(a+b)x+ab

Where, x=100 , a=3 , b=7

=100^2+(3+7)100+3\times7=100

=2+(3+7)100+3×7

=10000+(10)100+21=10000+(10)100+21

=10000+1000+21=10000+1000+21

=11021

Step-by-step explanation:

hope this helps you to you thank you

Answered by pulkitpargal
6

Step-by-step explanation:

103 x 107

100+3 x 100+7

(x+a) (x+b) = x2+(a+b) x + ab

100^2 + (3+7) 100 + 3.7

10000+1000+21

11021

Similar questions