evaluate using suitable identities 103x107
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6
Answer:
103×107
=(100+3)\times (100+7)=(100+3)×(100+7)
Using the identity (x+a)(x+b)=x^2+(a+b)x+ab(x+a)(x+b)=x
2 +(a+b)x+ab
Where, x=100 , a=3 , b=7
=100^2+(3+7)100+3\times7=100
=2+(3+7)100+3×7
=10000+(10)100+21=10000+(10)100+21
=10000+1000+21=10000+1000+21
=11021
Step-by-step explanation:
hope this helps you to you thank you
Answered by
6
Step-by-step explanation:
103 x 107
100+3 x 100+7
(x+a) (x+b) = x2+(a+b) x + ab
100^2 + (3+7) 100 + 3.7
10000+1000+21
11021
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