Math, asked by cletta74, 6 months ago

Evaluate using suitable identities (98)whole to the the power 3​

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Answered by vsu3436
2

Answer:

ANSWER

(98) 3

(100−2) 3

∴(a−b) 3=a 3 −b 3−3a 2b+3ab 2

(100−2) 3 =(100) 3−(2)3 −3×(100) 2×2+3×100×2 2

=1000000−3−60000+1200

=941192

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