Question

Evaluate using suitable identities :
( (ii) 102 x 106 (iii) 34 x 36​

Answer 1

Answer:

2) 10812

3) 1224

Step-by-step explanation:

we can use the following identity

$(x + y)(x - y) = {x}^{2} - {y}^{2}$

for solving both the questions.

Therefore We have:

ii)

$(102)(106) \\ \\ = (104 - 2)(104 + 2) \\ \\ = {104}^{2} - {2}^{2} \\ \\ = 10816 - 4 \\ \\ = 10812$

iii)

$(34)(36) \\ \\ = (35 - 1)(35 + 1) \\ \\ = {35}^{2} - {1}^{2} \\ \\ = 1225 - 1 \\ \\ = 1224$

I hope you are clear if not just comment me and mark me as the brainliest.

Answer 2

Answer:

1. 102 x 106

(104-2)(104+2)

(a^2-b^2)(a^2+b^2)=(a^2-b^2)

(104^2-2^2)

10816-4=10812

2. 34 x 36

(35-1)(35+1)

(35^2-1^2)

1225-1=1224

Step-by-step explanation: