Math, asked by Sanjana682, 1 year ago

Evaluate using suitable identity
0.6×0.6×0.6-0.3×0.3×0.3/0.6×0.6+0.6×0.3+0.3×0.3

Answers

Answered by Aarushi665
27

  \sf{ \frac{0.6 \times 0.6 \times 0.6 - 0.3 \times 0.3 \times 0.3}{0.6 \times 0.6 + 0.6 \times 0.3 + 0.3 \times 0.3} }

On taking 0.6 = a and 0.3 = b , the given expression becomes

   {\rm{ \frac{a \times a \times a- b \times b \times b}{a \times a+ a \times b + b\times b} }}

 \sf{ \implies{  \frac{{a}^{3}  -  {b}^{3} }{ {a}^{2}  + ab +  {b}^{2} }}}

 \rm  \fbox{ taking \:  \: {a}^{3}  -  {b}^{3}  = (a - b)( {a}^{2} +ab  +  {b}^{2}  )}

 \rm{ \implies{  \frac{(a - b)(  \cancel{{a}^{2} +ab  +  {b}^{2}  )} }{  \cancel{{a}^{2}  + ab +  {b}^{2} }}}}

  \rm\implies{a - b =0.6 - 0.3 }

 \rm  \fbox{{\therefore a - b =0.3 }}

Answered by shubhamnigam77
4

Answer:

Hay your answer is 0.3....

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