Question

Evaluate using suitable identity 2.07x1.93​

Answer 1

Answer:

2.07 x 1.93

(2 + 0.7) x (2 - 0.7)

We know that,

(a+b)×(a-b)= a²-b² --identity

therefore,

(2 + 0.7) x (2 - 0.7) = 2² - (0.7)²

= 4 - 0.49

= 3.51

2.07 x 1.93 = 3.51

Answer 2

Answer:

2.07 x 1.93

(2 + 0.7) x (2 - 0.7)

We know that,

(a+b)×(a-b)= a²-b² --identity

therefore,

(2 + 0.7) x (2 - 0.7) = 2² - (0.7)²

= 4 - 0.49

= 3.51

2.07 x 1.93 = 3.51