Question

evaluate using suitable identity

Answer 1

Answer:

On taking 0.6 = a and 0.3 = b, the given expression becomes,

axaxa-bxbxb/axa axb+bxb.

a³-b³/a²+ab+b².

a³-b³=a-b(a²+ab+b²).

(a−b)(a²+ab+b²)/a²+ab+b²

Now cancelling a²+ab+b² on both numerator and denominator it becomes,

=> a-b=0.6-0.3

=>0.3.