Evaluate using suitable identity a) 104 x 105 b) (98) 3 ANSWER THIS
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a) 104 ×105
(100+4)×(100+5)
using identity (x+a) (x+b) = x square ( a+b ) x + ab ,
where x =100 , a =4 , b=5.
(100 ) square +(4+5)(100)+(4×5)
10000 + (9) (100) + (20)
10000+900+20
=10920
b) 98³ can be written as (100-2)³
So, we'll use the identity -
(a-b)³= a³-b³-3a²b+3ab²
(100-2)³ = 100³ - 2³ - 3(100)²(2) + 3(100)(2)²
= 1000000 - 8 - 60000 + 1200
= 941192
Answer - 98 ³ = 941192
Hope this will help you :)
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