Math, asked by GREATLEARNING0, 8 months ago

Evaluate using suitable identity a) 104 x 105 b) (98) 3 ANSWER THIS

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Answered by niishaa
10

Answer:

a) 104 ×105

(100+4)×(100+5)

using identity (x+a) (x+b) = x square ( a+b ) x + ab ,

where x =100 , a =4 , b=5.

(100 ) square +(4+5)(100)+(4×5)

10000 + (9) (100) + (20)

10000+900+20

=10920

b) 98³ can be written as (100-2)³

So, we'll use the identity -

(a-b)³= a³-b³-3a²b+3ab²

(100-2)³ = 100³ - 2³ - 3(100)²(2) + 3(100)(2)²

              = 1000000 - 8  - 60000 + 1200 

              = 941192 

Answer - 98 ³ = 941192

Hope this will help you :)

Answered by singhshaurya895
5

Answer:

Hope it's helpful

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