Math, asked by sambhavtiwari24, 11 months ago

Evaluate: ( using suitable identity)
i) 49×51
ii) 198×202​
plz explain also
dont give foolish answers

Answers

Answered by ronald123oooocr7
5

Step-by-step explanation:

1.51×49

(50+1)×(50-1) (a^2+b^2)×(a^2-b^2)=a^2-b^2

50^2-1^2

2500-1

●ANS= 2499

2.202×198

(200+2)×(200-2) (a^2+b^2)×(a^2-b^2)=a^2-b^2

200^2-2^2

40000-4

●ANS=39996

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