Question

Evaluate using suitableldentities 2.(b-7) ²​

Answer 1

Answer:

Let (a-b)^7 = x. Then, we have:

(a-b)^7 = x => ln((a-b)^7) = lnx => 7(ln(a-b)) = lnx => e^[7(ln(a-b)) = e^(lnx) =>

x = e^[7(ln(a-b))]

Second solution:

(a-b)^7 = [b(a/b - 1)]^7 = (b^7)[(a/b - 1)^7] = (b^7)[(a/b)^7 – 7(a/b)^6 + 21(a/b)^5 - 35(a/b)^4 + 35(a/b)^3 - 21(a/b)^2 + 7(a/b) - 1]

Third solution:

Using Newton’s binomial, we take:

(a-b)^7 = a^7 – 7(a^6)b + 21(a^5)(b^2) - 35(a^4)(b^3) + 35(a^3)(b^4) - 21(a^2)(b^5) + 7a(b^6) - b^7

Step-by-step explanation:

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