Math, asked by happyhappy78, 11 months ago

evaluate using the suitable identities (999)3

Answers

Answered by priya783837

30

Answer:

(1000-1)³

(a-b)³= a³+b³-3ab(a-b)

= 1000³+1³-3× 1000 ×1(1000-1)

=1000000000-1-3000(999)

= 1000000000-1-2997000

= 1000000000-2997001

= 997002999

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