evaluate with suitable properties 26 into - 48 + - 48 into minus 36
Answers
26 × (– 48) + (– 48) × (–36)
(– 48) [ 26 +(–36) ]
(– 48) × [-10]
= 480
Answer:
Ncert solutions
Grade 7
Mathematics
Science
Chapters in NCERT Solutions - Mathematics, Class 7
Exercises in Integers
Question 5
Q5) Find the product, using suitable properties:
(a) 26 × (– 48) + (– 48) × (–36)
(b) 8 × 53 × (–125)
(c) 15 × (–25) × (– 4) × (–10)
(d) (– 41) × 102
(e) 625 × (–35) + (– 625) × 65
(f) 7 × (50 – 2)
(g) (–17) × (–29)
(h) (–57) × (–19) + 57
Solution 5)
(a) 26 × (– 48) + (– 48) × (–36)
(– 48) [ 26 +(–36) ]
(– 48) × [-10]
= 480
(b) 8 × 53 × (–125)
53\times[8\times(-125)]53×[8×(−125)]
53\times\left(-1000\right)53×(−1000)
=\ -53000= −53000
(c) 15 × (–25) × (– 4) × (–10)
15\times\left(-1000\right)\ =-1500015×(−1000) =−15000
(d) (– 41) × 102
-41\times\left[100+2\right]−41×[100+2]
-41\ \times\ 100\ +\left[\left(-41\right)\times2\right]−41 × 100 +[(−41)×2]
-4100+\left(-82\right)\ \ =\ -4182−4100+(−82) = −4182
(e) 625 × (–35) + (– 625) × 65
625\times\left[\left(-35\right)+\left(-65\right)\right]625×[(−35)+(−65)]
625\times\left(-100\right)\ \ =\ -62500625×(−100) = −62500
(f) 7 × (50 – 2)
7\times50-7\times27×50−7×2
350-14\ \ =\ 336350−14 = 336
(g) (–17) × (–29)
(-17)\times\left[(-30)\ +1\right](−17)×[(−30) +1]
\left(-17\right)\times30\ +\ \left(-17\right)\times1\(−17)×30 + (−17)×1
510\ +\left(-17\right)\ =\ 493510 +(−17) = 493
(h) (–57) × (–19) + 57
\left(-57\right)\times\left(-19\right)+57\times1(−57)×(−19)+57×1
57\times\left(19+1\right)57×(19+1)
57\ \times\ 20\ =114057 × 20 =1140
Step-by-step explanation:
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