Math, asked by Mgram1976, 1 year ago

Evaluate (x+1)(√2x+3)
Plz...help me my dear frnds....plz help me..
Its very very urgent.. :-(

Answers

Answered by techdoctuts
1
On multiplying the above expression, we get
 \sqrt{2}  {x}^{2}  +  \sqrt{2} x + 3x + 3 =
 \sqrt{2}  {x}^{2}  + x( \sqrt{2}  + 3) + 3
Answered by SenthilRaj123
0

Answer:

STEP-1 :

x+1 can be written as 12(2X+3)−12

or X+1=12(2X+3)−12 ….{You can verify it}

STEP-2:

Now, substitute 12(2X+3)−12 in place of X+1 in the integration expression

⌡ (X+1)√(2X+3)dx=⌡12(2X+3)−12√(2X+3)dx

⌡12(2X+3)−12√(2X+3)dx=⌡12(2X+3)32−12√(2X+3)dx

STEP-3:

Now the integration is simplified and can be solve easily

The result you would be getting is

12[(2X+3)525−(2X+3)323]

Hopefully I think you got the solution

HELP ME IF I MADE ANY MISTAKE.

THANKS IF THIS HELPS

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