Question

evaluate( x-1)(x+1)(x²+1)(x⁴-1) using identities​

Answer 1

Answer:

4755+7768(on 6&_+)6665;

Answer 2

Step-by-step explanation:

x+1/x][x-1/x][x²+1/x²][x⁴+1/x⁴]

= [x²- 1/x²][x²+1/x²][x⁴+1/x⁴]

=[(x²)²- (1/x²)²][x⁴+1/x⁴]

=[x⁴- 1/x⁴][x+1/x⁴]

=(x⁴)² - (1/x⁴)²

=x⁸-1/x⁸

hope it would be helpful

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