Question

EVALUATE (x-1/x+5)^2.

Answer 1

Step-by-step explanation:

given that : (x- 1/x + 5)^2

we can write it as (x +(-1/x)+ 5) ^2

it is in the form of (a+b+c)^2

we know that (a +b+c) ^2 =a^2+ b^2 +c^2 + 2ab + 2bc + 2ac

so, (x+(-1/x)+5)^2

= x^2 + (-1/x)^2 + 5^2 + 2(x)(-1/x)+2(-1/x)(5) +2(5)(x)

=x^2 + 1/x^2 + 25 + 2(-1) +2(-5/x)+2(5x)

=x^2 +1/x^2 + 25 -2 - 10/x + 10x

=x^2 +1/x^2 + 23 -10/x +10x

=x^2+ 1/x^2 +(23-10+10x^2)/x

=(x^4 + 1 +23x^2 -10x + 10x^3)/ x^2

let us take the whole equation =0

we get

x^4+10x^3+ 23x^2-10x+1=0

hence ,solved

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