evaluate x^12-y^12 using suitable formula
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(x^4)^3-(y^4)^3=(x^4-y^4)(x^8+y^8+x^4y^4)
=(x^2)^2-(y^2)^2(x^8+y^8+x^4y^4)
=(x^2-y^2)(x^2+y^2)(x^8+y^8+x^4y^4)
=(x-y)(x+y)(x^2+y^2)(x^8+y^8+x^4y^4) -Answer
in this sum mainly two formula use first is a^3-b^3=(a-b)(a^2+b^2+ab)
and second one is
a^2-b^2=(a-b)(a+b)
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=(x^2)^2-(y^2)^2(x^8+y^8+x^4y^4)
=(x^2-y^2)(x^2+y^2)(x^8+y^8+x^4y^4)
=(x-y)(x+y)(x^2+y^2)(x^8+y^8+x^4y^4) -Answer
in this sum mainly two formula use first is a^3-b^3=(a-b)(a^2+b^2+ab)
and second one is
a^2-b^2=(a-b)(a+b)
u mark me brainleast
sathishkumark4010:
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