Question

evaluate (x-2÷3y)^3 by using identity​

Answer 1

Step-by-step explanation:

Here is your answer:

We know that,

( a - b)³ = a³ - b³ -3ab (a-b)

Then,

(x- \frac{2}{3y})^{3}= x^{3}- (\frac{2}{3y})^{3}- \frac{2x}{y}(x- \frac{2}{3y})

⇒ x^{3}- \frac{8}{27y^{3}} - \frac{2x^{2}}{y}+ \frac{2x}{3y^{2}}

Answer 2

Answer:

Here is your answer:

We know that,

( a - b)³ = a³ - b³ -3ab (a-b)

Then,

(x- \frac{2}{3y})^{3}= x^{3}- (\frac{2}{3y})^{3}- \frac{2x}{y}(x- \frac{2}{3y})(x−3y2)3=x3−(3y2)3−y2x(x−3y2)

⇒ x^{3}- \frac{8}{27y^{3}} - \frac{2x^{2}}{y}+ \frac{2x}{3y^{2}}x3−27y38−y2x2+3y22x

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Hope this answer is helpful to you.