Question

evaluate : (-x+2y+3z)^2

Answer 1

Answer:

=x²+4y²+9z²-4xy-12yz+6xz

Step-by-step explanation:

(a+b+c)²=a²+b²+c²+2ab+2bc+2ac

a=-x

b=2y

c=-3z

Now put values.

=(-x)²+(2y)²+(-3z)²+2(-x)(2y)+2(2y)(-3z)+2(-x)(-3z)

=x²+4y²+9z²-4xy-12yz+6xz..