Question

evaluate (x+2y+z)2 maths ​

Answer 1

       $\underline{\bold{Answer:}}$

       $\boxed{(x+2y+z)^{2} = x^{2} + 4y^{2} + z^{2} + 4xy + 4yz + 2xz}$

       $\underline{\bold{Step-by-step-explaination:}}$

       $\text{We must evaluate }(x+2y+z)^{2}$

       $\text{We know that }(a+b+c)^{2} = a^{2} + b^{2} + c^{2} +2ab+2bc+2ac$

$\implies (x+2y+z)^{2} = (x)^{2}+(2y)^{2} +(z)^{2} + 2(x)(2y) + 2(2y)(z) + 2(x)(z)$

$\implies \boxed{(x+2y+z)^{2} = x^{2} + 4y^{2} + z^{2} + 4xy + 4yz + 2xz}$

Answer 2

Answer

x²+4y²+c²+4xy+4yz+2zx

Step-by-step explanation:

Evaluate (x+2y+z)2.