Physics, asked by Anonymous, 1 month ago

evaluate ∫ (x^3 -1/x+ 3x)dx

Answers

Answered by sejalbedre45

0

Answer:

∫x3+3x+4x−−√dx

=∫(x3x−−√+3xx−−√+4x−−√)dx

=∫x5/2dx+3∫x1/2dx+4∫x−1/2dx

=x7/27/2+3.x3/23/2+4.x1/21/2+c

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