Math, asked by eva875, 7 hours ago

evaluate : (x^3 + 2/x^3) (x - 2/x) ​

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Answered by zainab1372005
2

Answer:

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Reducing fractions to their lowest terms

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We think you wrote:

(x^3+2/x^3)(x-2/x)

This deals with reducing fractions to their lowest terms.

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STEP

1

:

2

Simplify —

x

Equation at the end of step

1

:

2 2

((x3)+————)•(x-—)

(x3) x

STEP

2

:

Rewriting the whole as an Equivalent Fraction

2.1 Subtracting a fraction from a whole

Rewrite the whole as a fraction using x as the denominator :

x x • x

x = — = —————

1 x

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

2.2 Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

x • x - (2) x2 - 2

——————————— = ——————

x x

Equation at the end of step

2

:

2 (x2 - 2)

((x3) + ————) • ————————

(x3) x

STEP

3

:

2

Simplify ——

x3

Equation at the end of step

3

:

2 (x2 - 2)

((x3) + ——) • ————————

x3 x

STEP

4

:

Rewriting the whole as an Equivalent Fraction :

4.1 Adding a fraction to a whole

Rewrite the whole as a fraction using x3 as the denominator :

x3 x3 • x3

x3 = —— = ———————

1 x3

Adding fractions that have a common denominator :

4.2 Adding up the two equivalent fractions

x3 • x3 + 2 x6 + 2

——————————— = ——————

x3 x3

Equation at the end of step

4

:

(x6 + 2) (x2 - 2)

———————— • ————————

x3 x

STEP

5

:

Trying to factor as a Sum of Cubes:

5.1 Factoring: x6+2

Theory : A sum of two perfect cubes, a3 + b3 can be factored into :

(a+b) • (a2-ab+b2)

Proof : (a+b) • (a2-ab+b2) =

a3-a2b+ab2+ba2-b2a+b3 =

a3+(a2b-ba2)+(ab2-b2a)+b3=

a3+0+0+b3=

a3+b3

Check : 2 is not a cube !!

Ruling : Binomial can not be factored as the difference of two perfect cubes

Polynomial Roots Calculator :

5.2 Find roots (zeroes) of : F(x) = x6+2

Polynomial Roots Calculator is a set of methods aimed at finding values of x for which F(x)=0

Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers x which can be expressed as the quotient of two integers

The Rational Root Theorem states that if a polynomial zeroes for a rational number P/Q then P is a factor of the Trailing Constant and Q is a factor of the Leading Coefficient

In this case, the Leading Coefficient is 1 and the Trailing Constant is 2.

The factor(s) are:

of the Leading Coefficient : 1

of the Trailing Constant : 1 ,2

Let us test ....

P Q P/Q F(P/Q) Divisor

-1 1 -1.00 3.00

-2 1 -2.00 66.00

1 1 1.00 3.00

2 1 2.00 66.00

Polynomial Roots Calculator found no rational roots

Trying to factor as a Difference of Squares:

5.3 Factoring: x2-2

Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)

Proof : (A+B) • (A-B) =

A2 - AB + BA - B2 =

A2 - AB + AB - B2 =

A2 - B2

Note : AB = BA is the commutative property of multiplication.

Note : - AB + AB equals zero and is therefore eliminated from the expression.

Check : 2 is not a square !!

Ruling : Binomial can not be factored as the difference of two perfect squares.

Multiplying exponential expressions :

5.4 x3 multiplied by x1 = x(3 + 1) = x4

Trying to factor as a Sum of Cubes:

5.5 Factoring: x6+2

Check : 2 is not a cube !!

Ruling : Binomial can not be factored as the difference of two perfect cubes

Final result :

(x6 + 2) • (x2 + 2)

———————————————————

x4

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