Math, asked by chilakarakshitha, 1 year ago

evaluate (x+3) whold cube

Answers

Answered by Anonymous
1
\huge\red{HELLO\:MATE}


\large{(x+3)^3}=x^3+9x^2 +27x+27}
Answered by Anonymous
4
hey mate your answer is here

(x + 3)³ = x³ + 3³ + 3× x × 3² + 3 × x² × 3
(x + 3)³ = x³ + 27 + 27x + 9x²
(x + 3)³ = x³ + 9x² + 27x + 27

thanks ☺
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