Math, asked by ushapooja340gmailcom, 1 year ago

evaluate( x - 3) wholed cube ​

Answers

Answered by risheshshukla12
0

Answer:

 {(x - y)}^{3}  =  {x}^{3}  -  {y}^{3 }  - 3xy(x - y)

 {(x - 3)}^{3} = x {}^{3}  -  {3}^{3 }  - 3.x. 3(x - 3

 =  {x}^{3}  - 27 - 9 {x}^{2}   +  27x

 =  {x}^{3 }  -  {9x}^{2}  + 27x - 27

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Answered by 7889236395n
0

Answer:

....x^2-9x^2+27x-27....

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