Question

Evaluate x^3+x^2-4x+13 when x = i+1 and when x=i-1

Answer 1

Answer:

If x= i+1, then P(x)= 7

If x= i-1, then P(x)= 19-10i

Step-by-step explanation:

P(x)= x^3+x^2-4x+13

x= i+1

P(i+1)= (i+1)^3+(i+1)^2-4(i+1)+13

= -i+1-3+3i-1+1+2i-4i-4+13

=7

x= i-1

P(i-1)= (i-1)^3+(i-1)^2-4(i-1)+13

= -i-1+3-3i-1+1-2i-4i+4+13

= 19-10i