Evaluate:∫|x^3-x|dx for x→ -1,2
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Evaluate:
(|x3−x|)(d)x
Evaluate for x=−1
(|(−1)3−(−1)|)(d)(−1)
(|(−1)3−(−1)|)(d)(−1)
=0
Answer: =0
Evaluate for x=2
(|23−2|)(d)(2)
(|23−2|)(d)(2)
=12d
Answer: =12d
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(|x3−x|)(d)x
Evaluate for x=−1
(|(−1)3−(−1)|)(d)(−1)
(|(−1)3−(−1)|)(d)(−1)
=0
Answer: =0
Evaluate for x=2
(|23−2|)(d)(2)
(|23−2|)(d)(2)
=12d
Answer: =12d
thanks
if you like my answer then mark it as brainliest it's comes above my answer and follow me
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