Question

evaluate x^3+y^3+8z^3-6xy
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Answer 1

Step-by-step explanation:

$x {}^{3} can \: be \: written \: as = (x) {}^{3}$

$(y) {}^{3} can \: be \: written \: as = (y) {}^{3}$

$8z {}^{3} can \: be \: written \: as = (2z) {}^{3}$

so, the factorization is :

$(x + y + 2z) {}^{3}$

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When ,

we follow

(x+y+z)^3 = x^3+y^3+z^3+2*x*y+2*y*z+2*x*z

So ,when we put up the values :

=x^3 +y^3+2z^3 + 2*xy+2*2yz-2*2xz

= x^3+y^3+8z^3+2xy+4yz-4xz

x^3+y^3+8z^3+6xy