Question

evaluate x^3+y^3+z^3-3xyz when x=-2,y=-1,z=3​

Answer 1

Answer:

0

Step-by-step explanation:

x^3+y^3+z^3 -3xyz

Let's substitute X,Y,Z values

-2^3+(-1)^3+3^3-3(-2)(-1)(3)

(-8)+(-1)+27-18

27-27=0

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Answer 2

Answer:

y=4*10^2

z=6*10^2

now put the values of in the equation 1

(2*10^2)^3 + (4*10^2)^3 + (6*10^2) ^3+ 3*

(2*4*6*10^(2*3)

so the final answer is

432*10^6

Step-by-step explanation:

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