Question

Evaluate ∫ x-½ cos√x dx​

Answer 1

Answer:

option is

D

2[

x

sin

x

+cos

x

].

I=∫cos

x

dx.

Put

x

=t so that

2

(x)

1

dx=dt

∴I=f(cost)2tdt=2∫tcostdt

Integrating by parts, we get

I=2[tsint−∫1.sintdt]

=2[tsint+cost]

=2[

x

sin

x

+cos

x

].

Hence, option 'D' is correct.