Math, asked by anshikap8269, 23 days ago

evaluate : [ x + y/2] ²​

Answers

Answered by annika13sai
0

Answer :

How to solve your problem

[

+

2

]

2

[x+\frac{y}{2}]^{2}

Simplify

1

Find common denominator

[

+

2

]

2

[x+\frac{y}{2}]^{2}

[

2

2

+

2

]

2

[\frac{2x}{2}+\frac{y}{2}]^{2}

2

Combine fractions with common denominator

Solution

(

2

+

2

)

Answered by sheeb12ansari
0

Given: The equation is[x+\frac{y}{2} ]^{2}

We have to evaluate the above equation.

As we know that,

(a+b)^{2} =a^{2} +2ab+b^{2}

By using the above identity, we are solving the given equation.

We are solving in the following way:

We have,

[x+\frac{y}{2} ]^{2}

Here,

a=x\\\\b=\frac{y}{2}

Now,

[x+\frac{y}{2} ]^{2}

\Rightarrow x^{2} +2\times x\times \frac{y}{2} +\frac{y^{2} }{4} \\\\\Rightarrow x^{2}+\frac{2xy}{2} + \frac{y^{2} }{4}\\\\\Rightarrow x^{2}+xy+\frac{y^{2} }{4}

Hence, the solution of the above equation isx^{2} +xy+\frac{y^{2} }{4}.

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