Question

evaluate (x2-ay)2 please send me solution​

Answer 1

Answer:

Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)

Proof : (A+B) • (A-B) =

A2 - AB + BA - B2 =

A2 - AB + AB - B2 =

A2 - B2

Note : AB = BA is the commutative property of multiplication.

Note : - AB + AB equals zero and is therefore eliminated from the expression.

Check : x2 is the square of x1

Check : a1 is not a square !!

Ruling : Binomial can not be factored as the difference of two perfect squares

Final result :

Final result : x2 - ay2

Hope it helps u(◍•ᴗ•◍)❤

Answer 2

$\huge \bf \ \red{ STEP 1:}$

Trying to factor as a Difference of Squares:

1 . 1 Factoring: x2-ay2

⠀

$\huge \bf \ \red{Theory : }$

A difference of two perfect squares, A2 - B2 can be factored into

(A+B) • (A-B)

⠀

$\huge \bf \ \red{ Proof : }$

(A+B) • (A-B) =

A2 - AB + BA - B2 =

A2 - AB + AB - B2 =

A2 - B2

⠀

$\huge \bf \ \red{ Note \ \: 1 : }$

AB = BA is the commutative property of multiplication.

⠀

$\huge \bf \ \red{Note \: \: 2. }$

AB + AB equals zero and is therefore eliminated from the expression.

⠀

$\huge \bf \ \red{ Check \: \: 1: }$

x2 is the square of x1

⠀

$\huge \bf \ \red{ Check \: \: 2: }$

a1 is not a square !!

⠀

$\huge \bf \ \red{Ruling : }$

Binomial can not be factored as the difference of two perfect squares

⠀

$\huge⚘ \bf \ \red{ Final \: Result :}$

⠀

⠀⠀x2 - ay2