Question

Evaluate: x² + y² + 3xy when x=2 and y=-1​

Answer 1

x = 2

y = -1

=>x² + y² + 3xy

• Put x = 2 and y = -1

=>(2)² + (-1)² + 3×2×(-1)

=> 4 + 1 - 6

=> -1

Answer is -1.

Answer 2

Answer:

x² +y² +3xy

= (2)² +(-1)² +3(2)(-1)

= 4 +1 -6

= -1

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