Question

Evaluate:(x²+y²+z²)(x+yz)​

Answer 1

Answer:

this is answer of this question

Answer 2

Answer:

Given data-

x+y+z=10

x^2+y^2+z^2=38

Now,we have a formulae -(x+y+z)^2=x^2+y^2+z^2+2(xy+yz+zx)

Putting known values in above formulae,we get

100=38+2(xy+yz+zx) or (xy+yz+zx)=62/2=31

Now,we are also given with x^3+y^3+z^3=160

We have a formulae -

x^3+y^3+z^3–3xyz=(x+y+z)(x^2+y^2+z^2-xy-yz-zx)

Putting known values in above equation,we get

160–3xyz=(10)(38–31) {Since,we have already got the value of xy+yz+zx}

160–3xyz=70 or 3xyz=90 or xyz=30

Thus,value of xyz=30

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Step-by-step explanation:

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