Math, asked by mishraprajna250, 9 months ago

evaluate x³-3x²-3x-1 if x = 1+2⅓+2⅔

Answers

Answered by singlaanmol354

Step-by-step explanation:

x = 1+2⅓+2⅔

x = 1+2⅓+2⅔x=1+7/3+8/3

x = 1+2⅓+2⅔x=1+7/3+8/3x=(3+7+8)/3

x = 1+2⅓+2⅔x=1+7/3+8/3x=(3+7+8)/3x=18/3

x = 1+2⅓+2⅔x=1+7/3+8/3x=(3+7+8)/3x=18/3x=6

x = 1+2⅓+2⅔x=1+7/3+8/3x=(3+7+8)/3x=18/3x=6x³-3x²-3x-1

x = 1+2⅓+2⅔x=1+7/3+8/3x=(3+7+8)/3x=18/3x=6x³-3x²-3x-1(6)^3-3(6)^2-3(6)-1

x = 1+2⅓+2⅔x=1+7/3+8/3x=(3+7+8)/3x=18/3x=6x³-3x²-3x-1(6)^3-3(6)^2-3(6)-1216-108-18-1

x = 1+2⅓+2⅔x=1+7/3+8/3x=(3+7+8)/3x=18/3x=6x³-3x²-3x-1(6)^3-3(6)^2-3(6)-1216-108-18-1216-108-19

x = 1+2⅓+2⅔x=1+7/3+8/3x=(3+7+8)/3x=18/3x=6x³-3x²-3x-1(6)^3-3(6)^2-3(6)-1216-108-18-1216-108-19216-127

x = 1+2⅓+2⅔x=1+7/3+8/3x=(3+7+8)/3x=18/3x=6x³-3x²-3x-1(6)^3-3(6)^2-3(6)-1216-108-18-1216-108-19216-127=89

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