evaluate ⅔x³&x-3 fori) x=-½ ii) x=¼ iii) x=3
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Answer:
Simplify the following expressions and evaluate them as directed:
x
2
2x+
x
2
for
x=
1
;
x=
−1
;
x=
2/3
and
x=
−1/2
ANSWER
x=
1;x=
−1;x=
2/3
x=
−1/2
x 2
2x+
x 2
x 2
2x+
x 2
3x
2
−
2x
3
+
x 4
x=
1
3x
2
−
2x
3
+
x 4
3(1)
2
−
2(1)
3
+
(1)
4
3×
1−
2×
1+
1
3−
2+
1=
2
x=
−1
3x
2
−
2x
3
+
x 4
3(4)
2
−
2(4)
3
+
(−1)
4
3×
1−
2×
(−1)+
1
3+
2+
1=
6
x=
2/3
3x
2
−
2x
3
+
x 4
3(2/3)
2
−
2(2/3)
3
+
(2/3)
4
3×
(4/9)−
2×
(8/27)+
(16/81)
(4/3)−
(16/27)+
(16/81)
(108−
48+
16)/81
(124−
48)/81
76/81
x=
−1/2
3x
2
−
2x
3
+
x 4
3(−1/2)
2
−
2(4/2)
3
+
(−1/2)
4
3×
(1/4)−
2×
(−1/8)+
(1/16)
(3/4)+
1/4+
(1/16)
(12+
4+
1)/16
17/16
Step-by-step explanation:
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