Evaluate x³ - y ³, if x+ y = 7 and x y = 12
Answers
Answer:
Let’s focus on equation 1. We want to isolate x. Subtract y from both sides;
x = 7 - y
Substitute x = 7 - y into equation 2: xy=12;
(7 - y)y = 12
Distribute;
7y - y^2 = 12
Subtract 12 from both sides;
7y - y^2 - 12
Order by terms;
-y^2 + 7y - 12
Quadratic Equation Formula; (-b +-√(b^2–4ac)) / (2a)
a = -1, b = 7, c = -12
Skipping the explanation of the formula because it is messy
y = 3
y = 4
Plug each solution into the original equation 1;
x + y = 7
Substitute y for 3 and y for 4;
x + 3 = 7
x + 4 = 7
Eq. 1; Subtract 3 from both sides
x = 4
Eq. 2; Subtract 4 from both sides
x = 3
Solutions: (3, 4) (4, 3)
Eq. 1: Substitute x for 3 and y for 4
3^3 + 4^3
Simplify
27 + 64
Combine like terms
91
Eq. 2: Substitute x for 4 and y for 3
4^3 + 3^3
Simplify
64 + 27
Combine like terms
91
Answer: 91
Answer:
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