evaluate x3 + y3 + z3 -3xyz when x=-2, y=-1 and z=3
Answers
Answered by
3
Answer:
x = -2
y = -1
z = 3
Step-by-step explanation:
(-2)³ + (-1)³+ ( 3)³ - 3(-2)(-1)(3)
-8 -1 +9 -18
-9+9-18
0-18
-18 is the answer
Answered by
3
Answer:
USE IDENTITY X3+Y3+z3-3XYz=(X+y+z)(x2+y2+z2-xy-zx-zy)
=(-2+-1+3))(x2+y2+z2-xy-zx-zy)
(-3+3))(x2+y2+z2-xy-zx-zy)
0*(x2+y2+z2-xy-zx-zy)
=0 answer
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