Math, asked by dhirendrat075, 7 months ago

evaluate x3 + y3 + z3 -3xyz when x=-2, y=-1 and z=3​

Answers

Answered by neeeru
3

Answer:

x = -2

y = -1

z = 3

Step-by-step explanation:

(-2)³ + (-1)³+ ( 3)³ - 3(-2)(-1)(3)

-8 -1 +9 -18

-9+9-18

0-18

-18 is the answer

Answered by kartavyasachan4000
3

Answer:

USE IDENTITY X3+Y3+z3-3XYz=(X+y+z)(x2+y2+z2-xy-zx-zy)

=(-2+-1+3))(x2+y2+z2-xy-zx-zy)

(-3+3))(x2+y2+z2-xy-zx-zy)

0*(x2+y2+z2-xy-zx-zy)

=0 answer

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