Question

(Evaluate) : xcos xdx​

Answer 1

Answer:

$x\sin x+\cos x +C$

Step-by-step explanation:

If $f(x)=x\cos x$

Then we have to find out

$\int f(x) dx$

$\text{Let} I=\int x\cos x dx$

$\implies I=x\int\cos x dx-\int 1.\int \cos xdx$ (Taking $x$ as first function and $\cos x$ as second function)

$\implies I=x\sin x-\int \sin x dx$

$\implies I=x\sin x+\cos x +C$ (Where C is a constant)

Hope this answer is helpful